C++中的函数重载
在同一个作用域中,可以为同一个函数名具有多个定义。函数的定义必须在参数列表中的参数类型和/或数量上彼此不同。您不能重载仅在返回类型上有所不同的函数声明。以下是使用相同函数print()打印不同数据类型的示例-
#include <iostream>
using namespace std;
class Box {
double length; // Length of a box
double breadth; // Breadth of a box
double height; // Height of a box
public:
double getVolume(void) {
return length * breadth * height;
}
void setLength( double len ) {
length = len;
}
void setBreadth( double bre ) {
breadth = bre;
}
void setHeight( double hei ) {
height = hei;
}
// Overload + operator to add two Box objects.
Box operator+(const Box& b) {
Box box;
box.length = this->length + b.length;
box.breadth = this->breadth + b.breadth;
box.height = this->height + b.height;
return box;
}
};
// Main function for the program
int main() {
Box Box1; // Declare Box1 of type Box
Box Box2; // Declare Box2 of type Box
Box Box3; // Declare Box3 of type Box
double volume = 0.0; // Store the volume of a box here
// box 1 specification
Box1.setLength(6.0);
Box1.setBreadth(7.0);
Box1.setHeight(5.0);
// box 2 specification
Box2.setLength(12.0);
Box2.setBreadth(13.0);
Box2.setHeight(10.0);
// volume of box 1
volume = Box1.getVolume();
cout << "Volume of Box1 : " << volume << endl;
// volume of box 2
volume = Box2.getVolume();
cout << "Volume of Box2 : " << volume << endl;
// Add two object as follows:
Box3 = Box1 + Box2;
// volume of box 3
volume = Box3.getVolume();
cout << "Volume of Box3 : " << volume << endl;
return 0;
}
尝试一下
编译并执行上述代码后,将产生以下结果-
Volume of Box1 : 210
Volume of Box2 : 1560
Volume of Box3 : 5400