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  Pandas - GroupBy

  • 简述

    任何groupby操作涉及对原始对象的以下操作之一。他们是 -
    • Splitting对象
    • Applying一个函数
    • Combining结果集
    在许多情况下，我们将数据拆分为多个集合，并对每个子集应用一些功能。在应用功能中，我们可以执行以下操作 -
    • 聚合− 计算汇总统计量
    • 转换− 执行一些特定于组的操作
    • 清洗− 在某些条件下丢弃数据
    现在让我们创建一个 DataFrame 对象并对其执行所有操作 - 
    
#import the pandas library
import pandas as pd
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
print df
    它的输出如下 - 
    
    Points   Rank     Team   Year
0      876      1   Riders   2014
1      789      2   Riders   2015
2      863      2   Devils   2014
3      673      3   Devils   2015
4      741      3    Kings   2014
5      812      4    kings   2015
6      756      1    Kings   2016
7      788      1    Kings   2017
8      694      2   Riders   2016
9      701      4   Royals   2014
10     804      1   Royals   2015
11     690      2   Riders   2017

  • 将数据拆分为组

    Pandas 对象可以拆分为它们的任何对象。有多种方法可以拆分对象，例如 -
    • obj.groupby('key')
    • obj.groupby(['key1','key2'])
    • obj.groupby(key,axis=1)
    现在让我们看看如何将分组对象应用于 DataFrame 对象

    例子

    
# import the pandas library
import pandas as pd
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
print df.groupby('Team')
    它的输出如下 - 
    
<pandas.core.groupby.DataFrameGroupBy object at 0x7fa46a977e50>

  • 查看组

    
# import the pandas library
import pandas as pd
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
print df.groupby('Team').groups
    它的输出如下 - 
    
{'Kings': Int64Index([4, 6, 7],      dtype='int64'),
'Devils': Int64Index([2, 3],         dtype='int64'),
'Riders': Int64Index([0, 1, 8, 11],  dtype='int64'),
'Royals': Int64Index([9, 10],        dtype='int64'),
'kings' : Int64Index([5],            dtype='int64')}

    例子

    Group by多列 - 
    
# import the pandas library
import pandas as pd
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
print df.groupby(['Team','Year']).groups
    它的输出如下 - 
    
{('Kings', 2014): Int64Index([4], dtype='int64'),
 ('Royals', 2014): Int64Index([9], dtype='int64'),
 ('Riders', 2014): Int64Index([0], dtype='int64'),
 ('Riders', 2015): Int64Index([1], dtype='int64'),
 ('Kings', 2016): Int64Index([6], dtype='int64'),
 ('Riders', 2016): Int64Index([8], dtype='int64'),
 ('Riders', 2017): Int64Index([11], dtype='int64'),
 ('Devils', 2014): Int64Index([2], dtype='int64'),
 ('Devils', 2015): Int64Index([3], dtype='int64'),
 ('kings', 2015): Int64Index([5], dtype='int64'),
 ('Royals', 2015): Int64Index([10], dtype='int64'),
 ('Kings', 2017): Int64Index([7], dtype='int64')}

  • 遍历组

    随着groupby手头的对象，我们可以像 itertools.obj 一样遍历对象。 
    
# import the pandas library
import pandas as pd
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
grouped = df.groupby('Year')
for name,group in grouped:
   print name
   print group
    它的输出如下 - 
    
2014
   Points  Rank     Team   Year
0     876     1   Riders   2014
2     863     2   Devils   2014
4     741     3   Kings    2014
9     701     4   Royals   2014
2015
   Points  Rank     Team   Year
1     789     2   Riders   2015
3     673     3   Devils   2015
5     812     4    kings   2015
10    804     1   Royals   2015
2016
   Points  Rank     Team   Year
6     756     1    Kings   2016
8     694     2   Riders   2016
2017
   Points  Rank    Team   Year
7     788     1   Kings   2017
11    690     2  Riders   2017
    默认情况下，groupby对象具有与组名称相同的标签名称。

  • 选择一个组

    使用get_group()方法，我们可以选择单个组。 
    
# import the pandas library
import pandas as pd
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
grouped = df.groupby('Year')
print grouped.get_group(2014)
    它的输出如下 - 
    
   Points  Rank     Team    Year
0     876     1   Riders    2014
2     863     2   Devils    2014
4     741     3   Kings     2014
9     701     4   Royals    2014

  • 聚合

    聚合函数为每个组返回一个聚合值。一旦group by创建对象后，可以对分组的数据执行多个聚合操作。
    一个明显的方法是通过聚合或等价物进行聚合agg方法 - 
    
# import the pandas library
import pandas as pd
import numpy as np
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
grouped = df.groupby('Year')
print grouped['Points'].agg(np.mean)
    它的输出如下 - 
    
Year
2014   795.25
2015   769.50
2016   725.00
2017   739.00
Name: Points, dtype: float64
    查看每个组大小的另一种方法是应用 size() 函数 - 
    
import pandas as pd
import numpy as np
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
Attribute Access in Python Pandas
grouped = df.groupby('Team')
print grouped.agg(np.size)
    它的输出如下 - 
    
         Points   Rank   Year
Team
Devils        2      2      2
Kings         3      3      3
Riders        4      4      4
Royals        2      2      2
kings         1      1      1

    一次应用多个聚合函数

    使用分组系列，您还可以通过list要么dict of functions进行聚合，并生成 DataFrame 作为输出 - 
    
# import the pandas library
import pandas as pd
import numpy as np
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
grouped = df.groupby('Team')
print grouped['Points'].agg([np.sum, np.mean, np.std])
    它的输出如下 - 
    
Team      sum      mean          std
Devils   1536   768.000000   134.350288
Kings    2285   761.666667    24.006943
Riders   3049   762.250000    88.567771
Royals   1505   752.500000    72.831998
kings     812   812.000000          NaN

  • 转换

    对组或列的转换返回一个对象，该对象的索引与被分组的大小相同。因此，转换应返回与组块大小相同的结果。 
    
# import the pandas library
import pandas as pd
import numpy as np
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
grouped = df.groupby('Team')
score = lambda x: (x - x.mean()) / x.std()*10
print grouped.transform(score)
    它的输出如下 - 
    
       Points        Rank        Year
0   12.843272  -15.000000  -11.618950
1   3.020286     5.000000   -3.872983
2   7.071068    -7.071068   -7.071068
3  -7.071068     7.071068    7.071068
4  -8.608621    11.547005  -10.910895
5        NaN          NaN         NaN
6  -2.360428    -5.773503    2.182179
7  10.969049    -5.773503    8.728716
8  -7.705963     5.000000    3.872983
9  -7.071068     7.071068   -7.071068
10  7.071068    -7.071068    7.071068
11 -8.157595     5.000000   11.618950

  • 过滤

    过滤根据定义的标准过滤数据并返回数据子集。这filter()函数用于过滤数据。 
    
import pandas as pd
import numpy as np
ipl_data = {'Team': ['Riders', 'Riders', 'Devils', 'Devils', 'Kings',
   'kings', 'Kings', 'Kings', 'Riders', 'Royals', 'Royals', 'Riders'],
   'Rank': [1, 2, 2, 3, 3,4 ,1 ,1,2 , 4,1,2],
   'Year': [2014,2015,2014,2015,2014,2015,2016,2017,2016,2014,2015,2017],
   'Points':[876,789,863,673,741,812,756,788,694,701,804,690]}
df = pd.DataFrame(ipl_data)
print df.groupby('Team').filter(lambda x: len(x) >= 3)
    它的输出如下 - 
    
    Points  Rank     Team   Year
0      876     1   Riders   2014
1      789     2   Riders   2015
4      741     3   Kings    2014
6      756     1   Kings    2016
7      788     1   Kings    2017
8      694     2   Riders   2016
11     690     2   Riders   2017
    在上述过滤条件中，我们要求返回参加过 3 次或以上 IPL 的团队。
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