指针传递给函数
Objective-C编程语言允许您将指针传递给函数。为此,只需将函数参数声明为指针类型。在一个简单的示例中,我们将一个无符号的长指针传递给一个函数,并更改该函数内部的值,该值会反映在调用函数中-
#import <Foundation/Foundation.h>
@interface SampleClass:NSObject
- (void) getSeconds:(int *)par;
@end
@implementation SampleClass
- (void) getSeconds:(int *)par {
/* get the current number of seconds */
*par = time( NULL );
return;
}
@end
int main () {
int sec;
SampleClass *sampleClass = [[SampleClass alloc]init];
[sampleClass getSeconds:&sec];
/* print the actual value */
NSLog(@"Number of seconds: %d\n", sec );
return 0;
}
2020-08-08 10:40:03.005 test[11928:4136] Number of seconds: 1596854402
该函数可以接受一个指针,也可以接受一个数组,如以下示例所示:
@interface SampleClass:NSObject
/* function declaration */
- (double) getAverage:(int *)arr ofSize:(int) size;
@end
@implementation SampleClass
- (double) getAverage:(int *)arr ofSize:(int) size {
int i, sum = 0;
double avg;
for (i = 0; i < size; ++i) {
sum += arr[i];
}
avg = (double)sum / size;
return avg;
}
@end
int main () {
/* an int array with 5 elements */
int balance[5] = {1000, 2, 3, 17, 50};
double avg;
SampleClass *sampleClass = [[SampleClass alloc]init];
/* pass pointer to the array as an argument */
avg = [sampleClass getAverage: balance ofSize: 5 ] ;
/* output the returned value */
NSLog(@"Average value is: %f\n", avg );
return 0;
}
2020-08-08 10:42:37.483 test[6612:332] Average value is: 214.400000