Java 示例 - 链式异常

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  问题描述

  如何使用 catch 处理链式异常？
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  解决方案

  此示例显示如何使用多个 catch 块处理链式异常。

  
  public class Main{
     public static void main (String args[])throws Exception { 
        int n = 20, result = 0;
        try { 
           result = n/0;
           System.out.println("The result is "+result);
        } catch(ArithmeticException ex) { 
           System.out.println ("Arithmetic exception occoured: "+ex);
           try { 
              throw new NumberFormatException();
           } catch(NumberFormatException ex1) {
              System.out.println ("Chained exception thrown manually : "+ex1);
           }
        }
     }
  }
  

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  结果

  上面的代码示例将产生以下结果。

  
  Arithmetic exception occoured : 
  java.lang.ArithmeticException: / by zero
  Chained exception thrown manually : 
  java.lang.NumberFormatException
  

  下面是Java中使用catch处理链式异常的另一个例子

  
  public class Main{
     public static void main (String args[])throws Exception  {
        int n = 20,result = 0;
        try{
           result = n/0;
           System.out.println("The result is"+result);
        }catch(ArithmeticException ex){
           System.out.println("Arithmetic exception occoured: "+ex);
           try{  
              int data = 50/0;  
           }catch(ArithmeticException e){System.out.println(e);}  
              System.out.println("rest of the code...");  
        }
     }
  }
  

  上面的代码示例将产生以下结果。

  
  Arithmetic exception occoured: java.lang.ArithmeticException: / by zero
  java.lang.ArithmeticException: / by zero
  rest of the code...