C语言 <ctype.h> ispunct() 函数

描述

C库函数int ispunct(int c) 检查所传递的字符是否为标点字符。标点符号是不是字母数字的任何图形字符（如isgraph）（如isalnum）。

声明

以下是ispunct()函数的声明。


int ispunct(int c);

参数

c - 这是要检查的字符。

返回值

如果c是标点符号，则此函数返回非零值（true），否则返回零（false）。

示例

以下示例显示ispunct()函数的用法-


#include <stdio.h>
#include <ctype.h>

int main () {
   int var1 = 't';
   int var2 = '1';
   int var3 = '/';
   int var4 = ' ';

   if( ispunct(var1) ) {
      printf("var1 = |%c| is a punctuation character\n", var1 );
   } else {
      printf("var1 = |%c| is not a punctuation character\n", var1 );
   }
   
   if( ispunct(var2) ) {
      printf("var2 = |%c| is a punctuation character\n", var2 );
   } else {
      printf("var2 = |%c| is not a punctuation character\n", var2 );
   }
   
   if( ispunct(var3) ) {
      printf("var3 = |%c| is a punctuation character\n", var3 );
   } else {
      printf("var3 = |%c| is not a punctuation character\n", var3 );
   }
   
   if( ispunct(var4) ) {
      printf("var4 = |%c| is a punctuation character\n", var4 );
   } else {
      printf("var4 = |%c| is not a punctuation character\n", var4 );
   }
   
   return(0);
}

尝试一下

让我们编译并运行上述程序，以产生以下结果-


var1 = |t| is not a punctuation character
var2 = |1| is not a punctuation character
var3 = |/| is a punctuation character
var4 = | | is not a punctuation character